Problem of the Month - June 2025
You will need two six-sided dice to play this game. Roll both dice and create a two digit number by taking the larger number followed by the smaller number. If the numbers are the same, then the two digit number is going to be either 11, 22, 33, 44, 55, or 66 depending on what you rolled. You win if you get a two digit number less than 50. Play the game 100 times to determine your experimental probability of winning.
Problem of the Month - May
A bag contains 5 blue blocks, 7 green blocks, and 6 red blocks. Blocks are selected randomly, one at a time, from the bag. What is the minimum number of blocks that need to be removed from the bag to be certain that there are three that are the same colour?
Solution
Problem of the Month - April 2025
You have a 7 minute and a 4 minute hourglass timer. How would you use these to measure 9 minutes?
Solution
Flip the 7 minute and 4 minute timer at the same time. When the 4 is done, flip it again. When the 7 minute timer is done, flip it again. When the 4 minute is done, flip the 7 minute timer. When the 7 minute timer is done, 9 minutes will have passed from the first time the timers were flipped.
Problem of the Month - March 2025
You roll a fair six sided die twice. Your score is whichever roll was higher. For example, if you rolled a 4 and then a 3, your score would be 4. What is the probability that your score will be 5?
Solution: If you roll a six sided die twice, there are 36 possible outcomes. The ones that would result in a score of 5 are:
1,5
2,5,
3,5
4,5
5,5
5,4
5,3
5,2
5,1
Problem of the Month - February 2025
In hockey, teams play three 20 minute periods. At the end of a hockey game, Team A had 4 goals and Team B had 2 goals. How many different Team A to Team B scores were possible at the end of the first period?
The possible scores were:
0-0,
0-1,
0-2,
1-0,
1-1,
1-2,
2-0,
2-1,
2-2,
3-0,
Problem of the Month - January 2025
You have a cube that has a side length of 5 cm. You want to cover it completely with cubes that have a side length of 1 cm so that you have a new, larger cube. How many 1 cm cubes will you need?
Solution:
You will need 218 one cm cubes. The side length of the new cube will be 7 cm, so the number of cubes can be found by evaluating 7x7x7-5x5x5=218.
What if the original cube had a side length of 6 cm?
Problem of the Month - December 2024
Pick a two digit number. Calculate 91 x (your number) x 111.
What do you notice?
Try it with other two digit numbers.
Why does this always happen?
Solution
91 x 111 =10101 so when you multiply a two digit number by 10101, you get the two digit number repeated three times.
Problem of the Month - November 2024
In the grid below, box A shares walls or corners with 3 other boxes, B, E, and F. Determine how many walls or corners each of the other boxes share.
Problem of the Month - October 2024
A string of consecutive whole numbers that adds to 2024 is 179+180+181+182+183+184+185+186+187+188+189.
Can you find another string of whole numbers that adds up to 2024?
Problem of the Month - September 2024
The diagonal of this 3 x 5 grid goes through 7 squares.
How many squares would the diagonal of a 12 x 20 grid go through?
What about a 6 x 9 grid?
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